Sunday, 2 October 2011

Coe questions

PFY p.121

Image001

A)50x10=500N

b)GPE=mgh

=50x10x4 = 2000J

c)KE= 1/2m v^2

2000=25 x v^2

80J=v^2

Collins, p.91

Image002

Q3: a) GPE=mgh

=35 x 10 x 30

= 10500J

B) KE=1/2m v^2

10500=1.5 x v^2

600J=v^2

c) Because there is friction between the sledge and the ice (=heat energy)

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